Pythagorean Triplets
Three numbers $2m, m^2 - 1, m^2 + 1$ form a Pythagorean triplet for any natural number $m > 1$:
$$(2m)^2 + (m^2 - 1)^2 = (m^2 + 1)^2$$
High-yield revision notes, key concepts, formulas, and CBSE board examination questions for Class 8 Mathematics.
Three numbers $2m, m^2 - 1, m^2 + 1$ form a Pythagorean triplet for any natural number $m > 1$:
$$(2m)^2 + (m^2 - 1)^2 = (m^2 + 1)^2$$
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