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CLASS 8 • MATHEMATICS • CHAPTER 1

Rational Numbers - Class 8 Mathematics | Krutsha AI

Complete Class 8 Mathematics Chapter 1 (Rational Numbers) NCERT revision notes, closure, commutative, associative properties, identities, and solved exemplars on Krutsha AI.

Direct Answer Capsule (Class 8 Overview)

A Rational Number is any number expressible in the form \(\frac{p}{q}\), where \(p\) and \(q\) are integers and \(q \neq 0\). In Class 8 NCERT Mathematics, rational numbers obey closure, commutativity, and associativity under addition and multiplication, with \(0\) as the additive identity, \(1\) as the multiplicative identity, and distributive property \(a(b + c) = ab + ac\).

High-Yield Chapter Key Takeaways

  • Standard Form: \(\frac{p}{q}\) where \(p, q\) are integers and \(q \neq 0\).
  • Addition and multiplication are commutative and associative; subtraction and division are NOT.
  • Additive Identity is \(0\) (\(a + 0 = a\)); Multiplicative Identity is \(1\) (\(a \times 1 = a\)).
  • Additive Inverse of \(\frac{a}{b}\) is \(-\frac{a}{b}\); Multiplicative Inverse (reciprocal) is \(\frac{b}{a}\).
  • Zero (\(0\)) has NO reciprocal because \(\frac{1}{0}\) is undefined.
  • There are infinitely many rational numbers between any two given rational numbers.

1. Definition and Standard Representation

A number that can be expressed in the form \(\frac{p}{q}\), where \(p\) and \(q\) are integers and \(q \neq 0\), is defined as a Rational Number (\(\mathbb{Q}\)). All natural numbers, whole numbers, integers, and terminating/repeating decimals are rational numbers.

Number Category Rational Form \(\frac{p}{q}\) Explanation
Zero (\(0\)) \(\frac{0}{1}, \frac{0}{5}, \frac{0}{-8}\) Rational because denominator \(q \neq 0\).
Integers (e.g., \(-7, 5\)) \(\frac{-7}{1}, \frac{5}{1}\) Any integer \(a\) can be written as \(\frac{a}{1}\).
Terminating Decimals (\(0.75\)) \(\frac{75}{100} = \frac{3}{4}\) Expressible as ratio of two integers.
Repeating Decimals (\(0.333\dots\)) \(\frac{1}{3}\) Non-terminating repeating decimals are rational.

2. Core Properties of Rational Numbers

Operations on rational numbers follow strict algebraic properties across addition, subtraction, multiplication, and division:

Property Addition (\(+\)) Subtraction (\(-\)) Multiplication (\(\times\)) Division (\(\div\))
Closure ✅ Closed: \(a + b \in \mathbb{Q}\) ✅ Closed: \(a - b \in \mathbb{Q}\) ✅ Closed: \(a \times b \in \mathbb{Q}\) ❌ Not Closed (if divisor is \(0\))
Commutative ✅ \(a + b = b + a\) ❌ \(a - b \neq b - a\) ✅ \(a \times b = b \times a\) ❌ \(a \div b \neq b \div a\)
Associative ✅ \((a + b) + c = a + (b + c)\) ❌ \((a - b) - c \neq a - (b - c)\) ✅ \((ab)c = a(bc)\) ❌ \((a \div b) \div c \neq a \div (b \div c)\)
Distributive \(a(b + c) = ab + ac\) and \(a(b - c) = ab - ac\) (Multiplication distributes over addition and subtraction).

3. Identities and Inverses

The Role of Zero (Additive Identity)

Zero is the additive identity for rational numbers:

94237a + 0 = 0 + a = a94237

Adding zero to any rational number leaves the number unchanged.

The Role of One (Multiplicative Identity)

One (\(1\)) is the multiplicative identity for rational numbers:

94237a \times 1 = 1 \times a = a94237

Multiplying any rational number by 1 yields the original number.

Additive Inverse (Negative of a Number)

For any rational number \(\frac{a}{b}\), its additive inverse is \(-\frac{a}{b}\):

94237\frac{a}{b} + \left(-\frac{a}{b} \right) = 094237

Example: Additive inverse of \(\frac{-5}{9}\) is \(\frac{5}{9}\).

Multiplicative Inverse (Reciprocal)

The reciprocal of a non-zero rational number \(\frac{a}{b}\) is \(\frac{b}{a}\):

94237\frac{a}{b} \times \frac{b}{a} = 194237

Warning: Zero (\(0\)) has no reciprocal because \(\frac{1}{0}\) is undefined.

4. Representation on a Number Line

Any rational number can be plotted on the real number line:

  1. To represent a proper fraction like \(\frac{4}{7}\), divide the unit distance between \(0\) and \(1\) into \(7\) equal segments. The \(4^{\text{th}}\) mark from \(0\) represents \(\frac{4}{7}\).
  2. To represent an improper fraction like \(\frac{8}{3}\), convert to a mixed fraction: \(\frac{8}{3} = 2\frac{2}{3}\). Locate the segment between \(2\) and \(3\), divide it into \(3\) equal intervals, and pick the \(2^{\text{nd}}\) subdivision.
  3. Negative rational numbers (e.g., \(-\frac{5}{6}\)) are plotted symmetrically to the left of zero.

5. Finding Rational Numbers Between Two Rational Numbers

Between any two rational numbers, there exist infinitely many rational numbers. Two reliable methods are used in NCERT Class 8:

Method 1: Common Denominator (LCM) Approach

Goal: Find \(5\) rational numbers between \(\frac{-2}{5}\) and \(\frac{1}{2}\).

Step 1: Equalize denominators using \(\text{LCM}(5, 2) = 10\):

94237\frac{-2}{5} = \frac{-2 \times 2}{5 \times 2} = \frac{-4}{10}, \quad \frac{1}{2} = \frac{1 \times 5}{2 \times 5} = \frac{5}{10}94237

Step 2: Select integers between \(-4\) and \(5\): \(-3, -2, -1, 0, 1, 2, 3, 4\).

Result: Five rational numbers are: \(\frac{-3}{10}, \frac{-2}{10}, \frac{-1}{10}, \frac{1}{10}, \frac{2}{10}\).

Method 2: Mean / Average Technique

For two rational numbers \(a\) and \(b\), the average \(\frac{a + b}{2}\) always lies strictly between \(a\) and \(b\) (\(a < \frac{a+b}{2} < b\)). Repeat successively to find as many numbers as required.

6. Solved NCERT Exemplar Problems

Exemplar 1: Using Properties to Simplify Expression

Problem: Evaluate using appropriate algebraic properties:

94237\frac{2}{5} \times \left(-\frac{3}{7} \right) - \frac{1}{14} - \frac{3}{7} \times \frac{3}{5}94237

Step 1: Rearrange terms using Commutative Property:

94237= \frac{2}{5} \times \left(-\frac{3}{7} \right) - \frac{3}{7} \times \frac{3}{5} - \frac{1}{14}94237

Step 2: Factor out \(\left(-\frac{3}{7} \right)\) using Distributive Property:

94237= \left(-\frac{3}{7} \right) \times \left[\frac{2}{5} + \frac{3}{5} \right] - \frac{1}{14}94237

Step 3: Simplify inside brackets:

94237= \left(-\frac{3}{7} \right) \times \left[\frac{5}{5} \right] - \frac{1}{14} = \left(-\frac{3}{7} \right) \times 1 - \frac{1}{14} = -\frac{3}{7} - \frac{1}{14}94237

Step 4: Common denominator (\(14\)):

94237= \frac{-6 - 1}{14} = -\frac{7}{14} = -\frac{1}{2}94237

7. Common Exam Pitfalls & Trap Avoidance

Critical Mistakes to Avoid in Class 8 Exams
  • Trap 1: Assuming Division is Commutative or Associative: \(8 \div 4 = 2\), but \(4 \div 8 = \frac{1}{2}\). Subtraction and division are NEVER commutative or associative.
  • Trap 2: Writing Reciprocal of Zero: The reciprocal of \(0\) is \(\frac{1}{0}\), which is undefined. \(0\) is the only rational number with no reciprocal.
  • Trap 3: Forgetting Sign when Computing Multiplicative Inverse: The reciprocal of \(-\frac{3}{7}\) is \(-\frac{7}{3}\). The negative sign is preserved (only the numerator and denominator flip).
  • Trap 4: Confusing Additive and Multiplicative Inverses: Additive inverse changes the sign (sum is \(0\)); multiplicative inverse flips the fraction (product is \(1\)).

Frequently Asked Questions

Is zero a rational number in Class 8 Mathematics?
Yes, zero is a rational number because it can be written in the form p/q with non-zero denominators, such as 0/1, 0/2, or 0/-5, where p=0 and q is any non-zero integer.
Which rational number is equal to its own reciprocal?
The rational numbers 1 and -1 are equal to their own reciprocals, because the reciprocal of 1 is 1/1 = 1, and the reciprocal of -1 is 1/(-1) = -1.
Why are subtraction and division not commutative for rational numbers?
Because changing the order of operands changes the numerical result. For example, 3/5 - 1/5 = 2/5, but 1/5 - 3/5 = -2/5. Similarly, (1/2) / (1/4) = 2, but (1/4) / (1/2) = 1/2.
How many rational numbers exist between any two rational numbers?
There are infinitely many rational numbers between any two distinct rational numbers, which can be found using the common denominator LCM method or the mean (a+b)/2 method.
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