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CLASS 8 • MATHEMATICS • CHAPTER 8

Algebraic Expressions and Identities

High-yield revision notes, key concepts, formulas, and CBSE board examination questions for Class 8 Mathematics.

Direct Answer Capsule (NCERT Class 8 Overview)

An algebraic expression is built by combining variables (unknown letters like $x, y$) and constants (numbers like $4, -7$) through addition, subtraction, multiplication, and division. An algebraic identity is an equality that remains true for all conceivable values of its variables, unlike an algebraic equation which holds true only for specific root values. NCERT Class 8 Mathematics Chapter 8 covers term factorization, coefficient identification, polynomial arithmetic, and the mastery of the four standard identities for rapid algebraic and numerical computation.

High-Yield Chapter Key Takeaways

  • Term Anatomy: In a term like $-5x^2y$, $-5$ is the numerical coefficient, while $x, x, y$ are the algebraic (literal) factors.
  • Only Like Terms Combine: Addition and subtraction are strictly permitted between like terms (same variables with identical powers). Unlike terms remain separated.
  • Polynomial Exponent Constraint: Expressions containing negative or fractional powers (such as $\frac{1}{x} = x^{-1}$ or $\sqrt{x} = x^{1/2}$) are not polynomials.
  • Identity vs. Equation: $(a + 1)(a + 2) = a^2 + 3a + 2$ is an identity (valid for all $a$), whereas $x^2 + 3x + 2 = 12$ is an equation (valid only for specific roots $x = 2, -5$).
  • Mental Math Power: Identities allow rapid evaluation of large numbers, e.g., $103 \times 97 = (100 + 3)(100 - 3) = 10000 - 9 = 9991$.

1. What is an Algebraic Expression?

In arithmetic, we deal with known numerical values like $5, 12, -9$. In algebra, we encounter situations where certain quantities are not known beforehand or can change. We denote these unknown or varying quantities using variables (commonly letters of the alphabet such as $x, y, z, a, b, l, m$).

When constants and variables are combined using arithmetic operations ($+, -, \times, \div$), we obtain an algebraic expression.

Geometric Representation on a Number Line: If a variable $x$ represents the position of a point $X$ on a number line with origin $O (0)$, then:
  • $x + 5$ is located 5 units to the right of $X$.
  • $x - 4$ is located 4 units to the left of $X$.
  • $2x + 1$ is obtained by first doubling the distance $OX$ and then shifting 1 unit to the right.

2. Terms, Factors, and Numerical Coefficients

To work with expressions methodically, we break them down into their constituent building blocks: terms, factors, and coefficients.

Expression Term Factors Numerical Coefficient
$7xy - 5x$ $7xy$ $7, x, y$ $+7$
$-5x$ $-5, x$ $-5$
$1 - 2y + 3y^2$ $1$ $1$ $1$ (Constant term)
$-2y$ $-2, y$ $-2$
$3y^2$ $3, y, y$ $+3$
$\frac{x}{2} - \frac{y}{3}$ $\frac{1}{2}x$ $\frac{1}{2}, x$ $+\frac{1}{2}$
$-\frac{1}{3}y$ $-\frac{1}{3}, y$ $-\frac{1}{3}$
$0.3a - 0.6ab$ $0.3a$ $0.3, a$ $+0.3$
$-0.6ab$ $-0.6, a, b$ $-0.6$

3. Classification of Expressions: Monomials, Binomials, Trinomials & Polynomials

Algebraic expressions are classified according to the count of unlike terms they contain:

  1. Monomial: An expression containing exactly one term.
    Examples: $4x^2$, $7xyz$, $-9$, $3l^2m$.
  2. Binomial: An expression containing exactly two unlike terms.
    Examples: $a + b$, $4l + 5m$, $2x - 3y$, $p^2 - q^2$.
  3. Trinomial: An expression containing exactly three unlike terms.
    Examples: $a + b + c$, $2x + 3y - 5$, $x^2 - 5x + 6$.
  4. Polynomial: An algebraic expression containing one or more terms with non-negative integer exponents on all variables and non-zero coefficients.
CBSE Board Alert — What is NOT a Polynomial?
For an expression to be a polynomial, all exponents of the variables MUST be whole numbers ($0, 1, 2, 3, \dots$).
  • $\frac{1}{x} + 3 = x^{-1} + 3$ is NOT a polynomial because the exponent $-1$ is negative.
  • $\sqrt{x} + 5 = x^{1/2} + 5$ is NOT a polynomial because the exponent $\frac{1}{2}$ is a fraction.
  • $\frac{2}{y^2} - y$ is NOT a polynomial because $y^{-2}$ has a negative exponent.

4. Like and Unlike Terms

Understanding the distinction between like and unlike terms is fundamental to all algebraic manipulations:

Golden Principle: In addition and subtraction, only like terms can be combined. If you try to add unlike terms like $3x + 5y$, the sum simply remains $3x + 5y$. They cannot be consolidated into $8xy$!

5. Addition and Subtraction of Algebraic Expressions

There are two primary methods for adding and subtracting expressions: the Horizontal Method and the Column Method.

Addition of Expressions

To add expressions, collect like terms together and add their numerical coefficients.

NCERT Solved Example Method Comparison
Add: $7x^2 - 4x + 5$, $9x - 10$, and $4x^2 - 3x + 7$.
Method 1 (Horizontal):
Sum $= (7x^2 - 4x + 5) + (9x - 10) + (4x^2 - 3x + 7)$
Group like terms: $= (7x^2 + 4x^2) + (-4x + 9x - 3x) + (5 - 10 + 7)$
Combine coefficients: $= (7 + 4)x^2 + (-4 + 9 - 3)x + (12 - 10)$
$= 11x^2 + 2x + 2$

Method 2 (Column Method):
Align like terms vertically:
$\phantom{+ 0}7x^2 - 4x + 5$
$\phantom{+ 0000} + 9x - 10$
$\underline{+ 4x^2 - 3x + 7}$
$= 11x^2 + 2x + 2$

Subtraction of Expressions (The Sign-Flip Rule)

When subtracting expression $B$ from expression $A$, remember that subtracting a number is the same as adding its additive inverse. Therefore, every term in the expression being subtracted has its sign reversed (+ becomes -, and - becomes +).

High-Yield CBSE Question Subtraction
Subtract $4a - 7ab + 3b + 12$ from $12a - 9ab + 5b - 3$.
Solution (Column Method):
Write the minuend on top and subtrahend underneath with aligned like terms:
$\phantom{- (}12a - 9ab + 5b - 3$
$\phantom{- (}\phantom{1}4a - 7ab + 3b + 12$
$\underline{\phantom{-(}(-) \quad (+) \quad (-) \quad (-)\phantom{0000}}$ (Reversed signs of lower row)
$= (12 - 4)a + (-9 + 7)ab + (5 - 3)b + (-3 - 12)$
$= 8a - 2ab + 2b - 15$

6. Multiplication of Algebraic Expressions

Multiplication in algebra relies on the commutative and associative laws of real numbers together with the laws of exponents ($x^m \cdot x^n = x^{m+n}$).

A. Multiplying a Monomial by a Monomial

Examples:

B. Multiplying a Monomial by a Polynomial

Apply the Distributive Law of Multiplication over Addition: $a(b + c) = ab + ac$.

C. Multiplying a Binomial by a Binomial (FOIL Method)

Multiply each term of the first binomial by every term of the second binomial: $$(a + b)(c + d) = a(c + d) + b(c + d) = ac + ad + bc + bd$$

Worked Numerical Binomial Multiplication
Multiply: $(2x + 3y)(3x + 4y)$
$= 2x(3x + 4y) + 3y(3x + 4y)$
$= (2x \cdot 3x) + (2x \cdot 4y) + (3y \cdot 3x) + (3y \cdot 4y)$
$= 6x^2 + 8xy + 9xy + 12y^2$
Combine like terms ($8xy + 9xy = 17xy$):
$= 6x^2 + 17xy + 12y^2$

7. What is an Identity? (Identity vs. Equation)

Students often confuse an algebraic identity with an algebraic equation. The distinction is critical:

Criterion Algebraic Identity Algebraic Equation
Definition An equality that is valid for all values of the variable(s). An equality that is valid only for specific value(s) of the variable (its roots).
Sample Equality $(a + 1)(a + 2) = a^2 + 3a + 2$ $x^2 + 3x + 2 = 12$
Test $x = 1$ LHS $= 2 \times 3 = 6$; RHS $= 1 + 3 + 2 = 6$. (LHS = RHS ✓) LHS $= 1 + 3 + 2 = 6 \neq 12$. (LHS $\neq$ RHS ✗)
Test $x = 5$ LHS $= 6 \times 7 = 42$; RHS $= 25 + 15 + 2 = 42$. (LHS = RHS ✓) LHS $= 25 + 15 + 2 = 42 \neq 12$. (LHS $\neq$ RHS ✗)
Solution Count Infinitely many solutions (holds universally). Finite roots (here, only $x = 2$ and $x = -5$).

8. The Four Standard Algebraic Identities

In NCERT Class 8, four standard algebraic identities are introduced. These identities must be thoroughly memorized and recognized in both forward (expansion) and reverse (factorization) directions.

Identity I • Square of a Sum
$(a + b)^2 = a^2 + 2ab + b^2$

The square of the sum of two terms equals the square of the first, plus twice their product, plus the square of the second.

Identity II • Square of a Difference
$(a - b)^2 = a^2 - 2ab + b^2$

The square of a difference equals the square of the first, minus twice their product, plus the square of the second. Notice that the last term is $+b^2$.

Identity III • Difference of Two Squares
$(a + b)(a - b) = a^2 - b^2$

The product of the sum and difference of two terms equals the difference between their individual squares.

Identity IV • Common First Term
$(x + a)(x + b) = x^2 + (a + b)x + ab$

Multiplying two binomials sharing a common first term $x$ yields $x^2$, plus the sum of constants times $x$, plus the product of constants.

Proofs and Derivations:

  1. Identity I: $(a + b)^2 = (a + b)(a + b) = a(a + b) + b(a + b) = a^2 + ab + ba + b^2 = a^2 + 2ab + b^2$.
    Geometric Meaning: A square of side $(a + b)$ has area $(a+b)^2$, which subdivides into a square of area $a^2$, a square of area $b^2$, and two identical rectangles of area $ab$.
  2. Identity II: $(a - b)^2 = (a - b)(a - b) = a(a - b) - b(a - b) = a^2 - ab - ba + b^2 = a^2 - 2ab + b^2$.
  3. Identity III: $(a + b)(a - b) = a(a - b) + b(a - b) = a^2 - ab + ba - b^2 = a^2 - b^2$.
  4. Identity IV: $(x + a)(x + b) = x(x + b) + a(x + b) = x^2 + bx + ax + ab = x^2 + (a + b)x + ab$.
Identity IV Useful Variants with Negative Signs:
  • $(x - a)(x + b) = x^2 + (b - a)x - ab$
  • $(x + a)(x - b) = x^2 + (a - b)x - ab$
  • $(x - a)(x - b) = x^2 - (a + b)x + ab$

9. Fast Mental Math Using Identities (CBSE Favorite Section)

Examiners frequently test students on computing arithmetic products without using long multiplication by decomposing numbers into base-10 sums or differences.

CBSE Exam Type Arithmetic Identity Numerical
Evaluate without direct multiplication: (i) $103^2$, (ii) $98^2$, (iii) $105 \times 95$, (iv) $103 \times 104$.
(i) Evaluate $103^2$:
Write $103 = (100 + 3)$. Apply Identity I with $a = 100, b = 3$:
$103^2 = (100 + 3)^2 = 100^2 + 2(100)(3) + 3^2$
$= 10000 + 600 + 9 = \mathbf{10609}$

(ii) Evaluate $98^2$:
Write $98 = (100 - 2)$. Apply Identity II with $a = 100, b = 2$:
$98^2 = (100 - 2)^2 = 100^2 - 2(100)(2) + 2^2$
$= 10000 - 400 + 4 = 9600 + 4 = \mathbf{9604}$

(iii) Evaluate $105 \times 95$:
Write $105 = (100 + 5)$ and $95 = (100 - 5)$. Apply Identity III:
$105 \times 95 = (100 + 5)(100 - 5) = 100^2 - 5^2$
$= 10000 - 25 = \mathbf{9975}$

(iv) Evaluate $103 \times 104$:
Write $103 = (100 + 3)$ and $104 = (100 + 4)$. Apply Identity IV with $x = 100, a = 3, b = 4$:
$103 \times 104 = (100 + 3)(100 + 4) = 100^2 + (3 + 4)(100) + (3 \times 4)$
$= 10000 + 700 + 12 = \mathbf{10712}$

10. Common CBSE Exam Traps & Mistakes

Top Mistakes Students Make in Exam Papers

  1. Omitting the Middle Term $2ab$: Writing $(a + b)^2 = a^2 + b^2$ is one of the most widespread errors. Always remember the cross-product term $+2ab$.
  2. Incorrect Sign in Identity II: Writing $(a - b)^2 = a^2 - 2ab - b^2$. Remember that $(-b)^2 = +b^2$, so the last term is strictly positive ($+b^2$).
  3. Combining Unlike Terms: Treating $2x + 3y$ as $5xy$ or $3x^2 + 2x$ as $5x^3$. You can only add coefficients of terms with identical variable factors.
  4. Squaring a Monomial Incorrectly: Writing $(3x)^2 = 3x^2$. The coefficient must also be squared: $(3x)^2 = 3^2 \cdot x^2 = 9x^2$.
  5. Sign Reversal in Subtraction: When asked to "subtract $P$ from $Q$", students write $P - Q$ instead of $Q - P$. Moreover, failing to distribute the negative sign across all terms inside the parentheses leads to full marks loss.

11. Solved High-Yield Exemplar Problems

Exemplar Problem 1 Identity Simplification
Simplify: $(4m + 5n)^2 + (5m + 4n)^2$
Expand each term using Identity I $(a + b)^2 = a^2 + 2ab + b^2$:
First term: $(4m + 5n)^2 = (4m)^2 + 2(4m)(5n) + (5n)^2 = 16m^2 + 40mn + 25n^2$
Second term: $(5m + 4n)^2 = (5m)^2 + 2(5m)(4n) + (4n)^2 = 25m^2 + 40mn + 16n^2$

Now add the two expansions together:
$= (16m^2 + 25m^2) + (40mn + 40mn) + (25n^2 + 16n^2)$
$= 41m^2 + 80mn + 41n^2$
Exemplar Problem 2 Algebraic Manipulation
If $x + \frac{1}{x} = 5$, find the value of $x^2 + \frac{1}{x^2}$.
Given: $x + \frac{1}{x} = 5$
Squaring both sides of the equation:
$$\left(x + \frac{1}{x}\right)^2 = 5^2$$ Using Identity I $(a + b)^2 = a^2 + 2ab + b^2$ with $a = x$ and $b = \frac{1}{x}$:
$$x^2 + 2(x)\left(\frac{1}{x}\right) + \left(\frac{1}{x}\right)^2 = 25$$ $$x^2 + 2(1) + \frac{1}{x^2} = 25$$ $$x^2 + \frac{1}{x^2} = 25 - 2$$ $$x^2 + \frac{1}{x^2} = \mathbf{23}$$
Exemplar Problem 3 Difference of Squares Application
Using $a^2 - b^2 = (a + b)(a - b)$, find $(1.02)^2 - (0.98)^2$.
Here $a = 1.02$ and $b = 0.98$.
$a^2 - b^2 = (a + b)(a - b)$
$= (1.02 + 0.98) \times (1.02 - 0.98)$
$= (2.00) \times (0.04)$
$= \mathbf{0.08}$

12. Frequently Asked Questions (Class 8 Algebra)

What is an algebraic expression and what are its components?
An algebraic expression is formed by combining variables (letters like $x, y$) and constants (numbers like $3, -5$) using fundamental arithmetic operations ($+, -, \times, \div$). Its components include:
  • Terms: Elements separated by $+$ or $-$ signs (e.g., in $4x^2 - 3xy$, the terms are $4x^2$ and $-3xy$).
  • Factors: Quantities multiplied together to form a term (e.g., $4, x, x$ are factors of $4x^2$).
  • Numerical Coefficient: The constant number multiplying the variable in a term (e.g., $-3$ is the coefficient of $-3xy$).
What is the difference between like and unlike terms?
Like terms have identical algebraic (literal) factors raised to the exact same powers (e.g., $7xy$ and $-4yx$). Unlike terms have different variables or variables raised to different powers (e.g., $3x^2$ and $3x$). Only like terms can be added or subtracted together.
What is the difference between an identity and an equation?
An identity is an equality that holds true for every single possible value of its variables (e.g., $(a+b)^2 = a^2 + 2ab + b^2$). An equation holds true only for specific root values of the variable (e.g., $2x + 3 = 11$ is true only when $x = 4$).
Why is $\frac{1}{x} + 5$ not considered a polynomial?
By definition, a polynomial requires that all exponents of the variables must be non-negative integers ($0, 1, 2, \dots$). In $\frac{1}{x} = x^{-1}$, the exponent is $-1$, which is negative; therefore, the expression is not a polynomial.
What are the four standard algebraic identities in NCERT Class 8?
The four standard identities are:
  1. $(a + b)^2 = a^2 + 2ab + b^2$
  2. $(a - b)^2 = a^2 - 2ab + b^2$
  3. $(a + b)(a - b) = a^2 - b^2$
  4. $(x + a)(x + b) = x^2 + (a + b)x + ab$
How can standard identities be used for quick arithmetic evaluation?
You can decompose numbers into convenient base-10 components:
  • $103^2 = (100 + 3)^2 = 100^2 + 2(100)(3) + 3^2 = 10000 + 600 + 9 = 10609$
  • $105 \times 95 = (100 + 5)(100 - 5) = 100^2 - 5^2 = 10000 - 25 = 9975$
  • $99 \times 101 = (100 - 1)(100 + 1) = 100^2 - 1 = 9999$
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