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CLASS 12 • PHYSICS • CHAPTER 2

Electrostatic Potential and Capacitance

High-yield revision notes, key concepts, formulas, and CBSE board examination questions for Class 12 Physics.

Electrostatic Potential ($V$)

The work done per unit positive charge in bringing it from infinity to a point without acceleration:

$$V(r) = \frac{1}{4\pi\varepsilon_0} \frac{q}{r}$$

$$\vec{E} = -\nabla V = -\frac{dV}{dr}\hat{r}$$


Capacitance of a Parallel Plate Capacitor

Capacitance is the charge-storing capability per unit potential difference: $C = \frac{Q}{V}$.

Parallel Plate Capacitor with Vacuum:

$$C_0 = \frac{\varepsilon_0 A}{d}$$

With Dielectric Medium of Constant $K$:

$$C = \frac{K\varepsilon_0 A}{d} = K C_0$$

Energy Stored in a Capacitor:

$$U = \frac{1}{2}CV^2 = \frac{Q^2}{2C} = \frac{1}{2}QV$$

Energy density: $u_E = \frac{1}{2}\varepsilon_0 E^2$.

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