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CLASS 10 • SCIENCE • CHAPTER 12

Electricity

High-yield revision notes, key concepts, formulas, and CBSE board examination questions for Class 10 Science.

Electric Current, Potential & Ohm's Law

$$I = \frac{Q}{t} \quad (\text{SI Unit: Ampere, A})$$

$$V = \frac{W}{Q} \quad (\text{SI Unit: Volt, V})$$

Ohm's Law:

At constant temperature, current flowing through a metallic conductor is directly proportional to potential difference across its terminals:

$$V \propto I \implies V = IR$$

Where $R$ is the electrical resistance of the conductor (SI Unit: $\Omega$, Ohm).


Resistance & Resistivity Factors

The resistance $R$ of a uniform conductor depends on:

  1. Directly proportional to length: $R \propto l$
  2. Inversely proportional to cross-sectional area: $R \propto \frac{1}{A}$
  3. Nature of material and temperature:

$$R = \rho \frac{l}{A}$$

Where $\rho$ is the Electrical Resistivity of the material (SI Unit: $\Omega\cdot\text{m}$).


Combination of Resistors

1. Resistors in Series:

Current remains identical through every resistor; total voltage divides ($V = V_1 + V_2 + V_3$):

$$R_{\text{series}} = R_1 + R_2 + R_3$$

2. Resistors in Parallel:

Voltage across each resistor is identical; total current splits ($I = I_1 + I_2 + I_3$):

$$\frac{1}{R_{\text{parallel}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$$


Heating Effect of Electric Current

Joule's Law of Heating:

Heat produced in a resistor is directly proportional to square of current, resistance, and time:

$$H = I^2Rt = VIt = \frac{V^2}{R}t$$

Electric Power ($P$):

$$P = VI = I^2R = \frac{V^2}{R} \quad (\text{SI Unit: Watt, W})$$

Commercial Unit of Energy:

$$1\text{ kilowatt-hour (kWh)} = 1\text{ unit} = 1000\text{ W} \times 3600\text{ s} = 3.6 \times 10^6\text{ Joules}$$

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